Minecraft Forums

Quote from Bulletin

Meh, so, you write data on it and then, how are you gona delete it?

Quote from gixxy

OH. ok. um... Let me wait till I get a better program to make the schematic. If anyone knows any (BESIDES MCEDIT) please tell me.


@smurfiod. Thank you. However there are still a few bugs when you hook it into clocks that need to be addressed and fixed. However yes, this will greatly increase storage space and such.

Quote from Arothar

I'm a little unsure what you're asking.

Can't you just use a monostable circuit to shorten the pulse from 2 ticks to 1 tick before you feed it into the counter?

Or for some reason do you actually need the counter to function on a 2 tick pulse?

Quote from Arothar

Sorry, don't use any third party editing software, so no can do. Instead I'll give you this stripped down version of the counter with instructions on how to wire it yourself! :wink.gif:



There are 9 glass blocks on top, 8 glass blocks and 1 wood block on the bottom.

Your input will be wired into all four pistons. The input has to be a 1-tick pulse.

The bottom right piston fires first, after no delay.

The top right and bottom left pistons fire at the same time, 2 ticks after the first piston.

The top left piston fires last, 4 ticks after the first piston (or 2 ticks after the middle two pistons).

The output consists of a torch and a repeater on one side, and redstone dust on the other side. Thus the dust only activates when the wood block is in place.

For this to work the way you want it, feed the output into the input after a 6 tick delay. Make sure it's still a 1-tick pulse.

If you have any other questions, let me know.

Quote from Arothar

I think this is what you're looking for, although I'm not 100% sure what you wanted.



The input is the cobblestone block in the bottom right with the button on it. After that block receives 17 inputs, the output will pulse once. As you can see, the output is fed back into the input (after 8 ticks of delay), which resets the counter.

Edit: Thus on every 17th pulse, the output is briefly triggered, which is what I gathered you were asking for...

Quote from Hans Lemurson

Hmm...doing a multiplication algorithm for and you want to make it stop when it's done 17 shifts.

How frequently do the shifts occur?

If ring-counters don't work (I have no idea why they wouldn't), then I think your best bet would actually be to make a 5-bit binary counter which gets set to start at 10001 and then receives a signal to decrement every time a "Shift Right" happens until it hits 00000 and you tell the algorithm to stop. You'll need to use a binary counter design which can be easily set though, which other than size is their main advantage over Ring Counters.

Reading about Booth's algorithm is quite interesting.

Quote from Hans Lemurson

17 huh? Binary lovers won't be happy about that.

Question: Does it ever need to get reset before reaching 17?

If not, I'd advise looking into a piston-device which pushes blocks in a square loop. All of the blocks should be glass except for one solid one which can conduct redstone charge. Every "input" will cause the loop to rotate by one block until the solid block is finally in position in front of the detector.

Quote from bitsNbytes

I don't think there are any smaller full adders that are 1-block wide

Quote from Tueman

Ok,so I'm gonna make a minecart race where the players in the minecarts need to hit a button on a block as soon as they reach a speeding point, which is a speed rail with a button next to it. When they hit the button, the rail turns on and pushes the player forward. Every once in a while, there would be a detector rail that turns on a trap like falling lava or sand. The point is, will it work? How can I make it better? And and suggestions for traps? Thank you.

Quote from bitsNbytes

I made one.

http://www.planetminecraft.com/project/gggsgfsg/

sorry to steal the spotlight OP :biggrin.gif:

p.s. it's impossible to make a full-adder 1-block wide. the best you can get is a 2-wide tileable (effectively 1-wide).