Okay 1st off this is NOT a do my homework post. It is only a question due to the textbook being so vague.
I've looked all over Google and i cant find my answer.
This is Algebra 1, Perpendicular and parallel lines.
The textbook says "Write the slope intercept form of an equation of a line that passes through the given point and is parallel to the graph of the equation." An example of one of the problems is (2, -7) y=x-2

It means it wants you to give an equation of a line that is parallel to y=x-2, but it also has to pass through (2, -7). Since you know the slope (which is 1)is the same because it's parallel to the given line, you can use point-slope form to find the equation of a line that is parallel to y=x-2 and passes through (2, -7).

It means it wants you to give an equation of a line that is parallel to y=x-2, but it also has to pass through (2, -7). Since you know the slope (which is 1)is the same because it's parallel to the given line, you can use point-slope form to find the equation of a line that is parallel to y=x-2 and passes through (2, -7).

Google searching math problems is not the best thing to do when your trying to type in (2, -7) y=x-2 or whatever you typed in its not ment for that (fyi).

Wait... so what do I do with the y intercept (:cool.gif: from the given equation?

What method did you use to find the y-intercept? If you plugged the point in to y=mx+b and solved for b, then you just replace b with -9 in the equation so it should turn out y=x-9.

What method did you use to find the y-intercept? If you plugged the point in to y=mx+b and solved for b, then you just replace b with -9 in the equation so it should turn out y=x-9.

isnt b the y intercept? :tongue.gif: thats what our teacher told usbasically what my question is was when I have y=x-2 and I convert to point slope, what do I do with -2

Well if you learned about point slope, you can use it. when you use point-slope form, you should get (y-(-7))=1(x-2), since you're using (2, -7) to find the y-intercept. It simplifies to y+7=x-2, then y=x-9.

You can also use the regular slope-intercept form. If you start with y=mx+b, and plug in -7 for y, 2 for x, and 1 for m since it's the slope and solve for b, it simplifies to -7=(1)(2)+b, then -7=2+b, then -9= b, which is the y-intercept. So if you use the information you have (slope is 1, y-intercept is -9), you can write an equation for it.

I would suggest the second method if you don't know point-slope form well.

I've looked all over Google and i cant find my answer.

This is Algebra 1, Perpendicular and parallel lines.

The textbook says "Write the slope intercept form of an equation of a line that passes through the given point and is parallel to the graph of the equation." An example of one of the problems is (2, -7) y=x-2

What does the textbook mean???

The Answer:

omg thank you!!!

No problem, if you need more help you can ask me, I'm in AP Calculus.

What method did you use to find the y-intercept? If you plugged the point in to y=mx+b and solved for b, then you just replace b with -9 in the equation so it should turn out y=x-9.

isnt b the y intercept? :tongue.gif: thats what our teacher told usbasically what my question is was when I have y=x-2 and I convert to point slope, what do I do with -2

You can also use the regular slope-intercept form. If you start with y=mx+b, and plug in -7 for y, 2 for x, and 1 for m since it's the slope and solve for b, it simplifies to -7=(1)(2)+b, then -7=2+b, then -9= b, which is the y-intercept. So if you use the information you have (slope is 1, y-intercept is -9), you can write an equation for it.

I would suggest the second method if you don't know point-slope form well.

Thanks for the help!

If you need more math help you can ask me if you want.