I usually don't ask for math help on a forum but this is an exception I guess? I am supposed to turn an equation into y=mx+b form and on some of them I'm confused.

For example:
x+5y=15

x-6y=2

And ones like that. The thing that confuses me is that the x isn't multiplied by another number and I don't know how to do it.

I usually don't ask for math help on a forum but this is an exception I guess? I am supposed to turn an equation into y=mx+b form and on some of them I'm confused.

For example:
x+5y=15

x-6y=2

And ones like that. The thing that confuses me is that the x isn't multiplied by another number and I don't know how to do it.

Maybe this will help you.
There is a coefficient (number) in front of the X. It is not written because it is a placeholder. The number in front of the X is 1. So the problem you listed as an example, x+5y=15. Is actually 1X+5Y=15. The reason the 1 isn't shown is because it does nothing but holds a place. So whenever there is no coefficient (number) in front of a variable (letter) you simply do the problem like normal. If you still don't get it let me know!

I usually don't ask for math help on a forum but this is an exception I guess? I am supposed to turn an equation into y=mx+b form and on some of them I'm confused.

For example:
x+5y=15

x-6y=2

And ones like that. The thing that confuses me is that the x isn't multiplied by another number and I don't know how to do it.

You just have to try to get y by itself. M in this case would just be 1. Here, I'll do the first one for you:

x + 5y = 15
Subtract x from both sides
5y = 15 - x
Divide both sides by 5
y = 3 - x/5
Rewrite to proper y = mx + b form
y = (-1/5)x + 3

1. Subtract 2 from each side: x - 2 - 6y = 0
2. Add 6y to each side: x - 2 = 6y
3. Flip the sides: 6y = x - 2
4. Divide each side by 6: y = (1/6)x - (1/3)
Also written as y = (x/6) - (1/3)

My experience: I've taken Algebra 1 two years ago, and am taking an Honors Algebra 2 class this year.

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I usually don't ask for math help on a forum but this is an exception I guess? I am supposed to turn an equation into y=mx+b form and on some of them I'm confused.

For example:
x+5y=15

x-6y=2

And ones like that. The thing that confuses me is that the x isn't multiplied by another number and I don't know how to do it.

Put the x on the other side of the equals side and divide by whatever number is with the y for example:
x+5y=15
5y=-x+15
y=-1/5x+3

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I usually don't ask for math help on a forum but this is an exception I guess? I am supposed to turn an equation into y=mx+b form and on some of them I'm confused.

For example:
x+5y=15

x-6y=2

And ones like that. The thing that confuses me is that the x isn't multiplied by another number and I don't know how to do it.

I'll assume you're either in beginning high school math, or you're a support math class in college. Either way, I can help (I think).

Okay, y=mx+b form is actually -REALLY- common in math, you'll see it a LOT, so it's good you're addressing this problem now.

These problems are simple divide/multiply issues, so keep an open mind, okay?

We'll tackle the first one now: x+5y=15

Well, that essentially is saying mx+y=b, all you need to do is switch stuff around to make y=mx+b, really.

So you'd do 5y=-x+15 (Remember to change the sign (Positive or negative) when going from one side of the equation to the other).
Now, you need to make that pesky 5y turn into just y. Best way: Divide. Now, to do this, you'll need to divide BOTH sides by 5 to ensure that every part is getting an equal part of the solution.

In short, it'd be (5y/5)= (-x/5) + (15/5)
5y/5 = y
-x/5 = -1x/5 (you can't simplify it, so don't get so worked up over it.)
15/5 = 3

Thanks. I guess what confused me is when you divide 5 by everything. I didn't know if it was supposed to be y=x/5 + 3 or what you said. I needed that help :smile.gif:

Math isn't my best subject, I try really hard to get good notes but sometimes I read them over and need help. I pay attention very well.

Thanks. I guess what confused me is when you divide 5 by everything. I didn't know if it was supposed to be y=x/5 + 3 or what you said. I needed that help :smile.gif:

you welcome. :smile.gif:

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For example:

x+5y=15

x-6y=2

And ones like that. The thing that confuses me is that the x isn't multiplied by another number and I don't know how to do it.

PAY ATTENTION IN CLASS is all i got to say :tongue.gif:

Subtract or add x depending on the sign

The laws of magic are absolute. The laws of physics are optional.5y= -x + 15

-6y= -x +2

u divide both sides by the coefficient of y, (which would be 5 and -6 in this case.)

y= -1/5x + 3

y= 1/6x - 1/3

First example

x+5y=15

5y=-x+15

y=-1/5x+3

Basically what you need to do is SUBTRACT x.

Second example:

x-6y=2

-6y=x+2

y=-1/6x-1/3

I hope this has helped.

There is a coefficient (number) in front of the X. It is not written because it is a placeholder. The number in front of the X is 1. So the problem you listed as an example, x+5y=15. Is actually 1X+5Y=15. The reason the 1 isn't shown is because it does nothing but holds a place. So whenever there is no coefficient (number) in front of a variable (letter) you simply do the problem like normal. If you still don't get it let me know!

5y = 2 - x //Subtract x from both sides

y = 2/5 - x/5 //Divide both sides by 5

y = -x/5 + 2/5 //Associative Property

You just have to try to get y by itself. M in this case would just be 1. Here, I'll do the first one for you:

EDIT: unholy ninja

1. Subtract x from each side: 5y = -x + 15

2. Divide each side by 5: y = (-x/5) + 3

Also written as y = (-1/5)x + 3

1. Subtract 2 from each side: x - 2 - 6y = 0

2. Add 6y to each side: x - 2 = 6y

3. Flip the sides: 6y = x - 2

4. Divide each side by 6: y = (1/6)x - (1/3)

Also written as y = (x/6) - (1/3)

My experience: I've taken Algebra 1 two years ago, and am taking an Honors Algebra 2 class this year.

Edit: very, very, very, very ninja'd.

If you're going to respond to me, please quote my post so that I'm notified.My youtube channel: contains Terraria and Minecraft videos (especially Minecraft).Put the x on the other side of the equals side and divide by whatever number is with the y for example:

x+5y=15

5y=-x+15

y=-1/5x+3

I'll assume you're either in beginning high school math, or you're a support math class in college. Either way, I can help (I think).

Okay, y=mx+b form is actually -REALLY- common in math, you'll see it a LOT, so it's good you're addressing this problem now.

These problems are simple divide/multiply issues, so keep an open mind, okay?

We'll tackle the first one now: x+5y=15

Well, that essentially is saying mx+y=b, all you need to do is switch stuff around to make y=mx+b, really.

So you'd do 5y=-x+15 (Remember to change the sign (Positive or negative) when going from one side of the equation to the other).

Now, you need to make that pesky 5y turn into just y. Best way: Divide. Now, to do this, you'll need to divide BOTH sides by 5 to ensure that every part is getting an equal part of the solution.

In short, it'd be (5y/5)= (-x/5) + (15/5)

5y/5 = y

-x/5 = -1x/5 (you can't simplify it, so don't get so worked up over it.)

15/5 = 3

Take those answers and put 'em in y=mx+b form.

y=-1x/5+3

Ta-Da! I hope I helped a bit.

Math isn't my best subject, I try really hard to get good notes but sometimes I read them over and need help. I pay attention very well.

Thanks. I guess what confused me is when you divide 5 by everything. I didn't know if it was supposed to be y=x/5 + 3 or what you said. I needed that help :smile.gif:

you welcome. :smile.gif: