The line AB is the tangent of the circle
The angle ATP is 58º
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Why am I asking this?
I'm retaking my GCSEs for maths, I got to this question having not skipped a single previous question. I had no idea what I was doing - I knew I'd learned how to solve this but I couldn't remember. I ended up doing some really long sloppy calculation and it was obviously a 50/50 chance I'd get it right. Good enough odds for me since it's worth 5 marks.
I want to know the ACTUAL answer though, so I know before August or whatever date, if I got it wrong or right.
And yes, I remembered and re-drew the question o_o...
I ****ing love that stuff. I could not understand half the **** we learned in Geometry (ninth grade ftl), but I mastered circles/arcs/angles and whatnot.
While we're all still having fun, here's another one for you (I know the answer already, but I like to see which approach people take with it):
You have an equilateral triangle ABC with AB = BC = AC = 1. A point, P is picked in the interior of the triangle and line segments AP, BP, and CP are constructed. Given angles APB, BPC, and CPA what are the lengths of segments AP, BP, and CP?
It'll help to draw a picture. Also, I don't expect a final monolithic expression for each length, since it may or may not be messy (when I solved the problem I didn't carry the algebra all the way through, I simply left it in two parts because algebra is boring and I didn't see much potential for simplification).
Rollback Post to RevisionRollBack
Never attribute to malice what can adequately be explained by incompetence.
While we're all still having fun, here's another one for you (I know the answer already, but I like to see which approach people take with it):
You have an equilateral triangle ABC with AB = BC = AC = 1. A point, P is picked in the interior of the triangle and line segments AP, BP, and CP are constructed. Given angles APB, BPC, and CPA what are the lengths of segments AP, BP, and CP?
It'll help to draw a picture. Also, I don't expect a final monolithic expression for each length, since it may or may not be messy (when I solved the problem I didn't carry the algebra all the way through, I simply left it in two parts because algebra is boring and I didn't see much potential for simplification).
Given angles APB, BPC, and CPA are... what? What are the angles? How do we solve it without the angles?
Find the angle OTQ
The line AB is the tangent of the circle
The angle ATP is 58º
----------
Why am I asking this?
I'm retaking my GCSEs for maths, I got to this question having not skipped a single previous question. I had no idea what I was doing - I knew I'd learned how to solve this but I couldn't remember. I ended up doing some really long sloppy calculation and it was obviously a 50/50 chance I'd get it right. Good enough odds for me since it's worth 5 marks.
I want to know the ACTUAL answer though, so I know before August or whatever date, if I got it wrong or right.
And yes, I remembered and re-drew the question o_o...
THIS IS A NON-CALCULATOR QUESTION
Angle TQP = Angle ATP (=58°) (Angle between chord and tangent)
OP = OT (circle)
PQ = QT
OQ = OQ } Triangle QPO is congruent with Triangle TQO. (FFF)
Angle OQP = Angle OQT = 0.5 * Angle PQT = 0.5 * 58° = 29°
OT = OQ } Triangle TOQ is an isosceles triangle.
Angle OTQ = Angle OQT = 29°
Q.E.D. Mother****ers.
You mean PQ = QT.
There is a reason why I am retaking GCSE Maths in college you know.
You heard that, green and red.
You have an equilateral triangle ABC with AB = BC = AC = 1. A point, P is picked in the interior of the triangle and line segments AP, BP, and CP are constructed. Given angles APB, BPC, and CPA what are the lengths of segments AP, BP, and CP?
It'll help to draw a picture. Also, I don't expect a final monolithic expression for each length, since it may or may not be messy (when I solved the problem I didn't carry the algebra all the way through, I simply left it in two parts because algebra is boring and I didn't see much potential for simplification).
Eh yeah, typo there. I'll edit it.
You heard that, green and red.
Given angles APB, BPC, and CPA are... what? What are the angles? How do we solve it without the angles?
Did you word that wrong or something? :|
You heard that, green and red.
Awesome, you necro'd a 2 year old topic just so you could be wrong. You're such a winner.