Please don't start a war.. This is supposed to be a topic about sticky rails. Not minecraft physics. But if you do want to argue on physics. Go to the appropriate threads and talk about AE's matter to energy system or endermen.. maybe even creepers?
Wow. Put a minecart on a sloped rail, walk off a cliff, throw an item out of your inventory, guess what? falls! why? because yes, gravity does not apply to all blocks, but it does apply to some entities (including minecarts)
Edit: there should be a rule that only allows people with reasonable intelligence to suggest mods and features for the game.
Over 90% of all the things in Minecraft ignore gravity. Also, THIS IS A VIDEO GAME! Stop trying to apply real world logic to it. Gravity exists, but only to CERTAIN THINGS! And there are PLENTY of ways around gravity. In Minecraft, gravity isn't universal.
Oh, and if your rule is implemented, then i guess you won't be able to post any suggestions.
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Puella Magi Madoka Magicka is an awesome, feel-good, cutesy anime. You should watch it!
I see failures under a tree aka the Online dater owners who have the marry plugin because they're loners and cant get a real girlfriend or boyfriend because they apparently are inmature 16 year olds to under stand what a real girlfriend in because they sit in their room online dating on roblox or minecraft with some 8 year old girl and the boy being 18. online daters are excuses.
Over 90% of all the things in Minecraft ignore gravity. Also, THIS IS A VIDEO GAME! Stop trying to apply real world logic to it. Gravity exists, but only to CERTAIN THINGS! And there are PLENTY of ways around gravity. In Minecraft, gravity isn't universal.
Oh, and if your rule is implemented, then i guess you won't be able to post any suggestions.
Yes, but even so im fairly sure a sticky rail will slow down the minecart if anything. Regardless it's not Mojang even looks at this forum so why do I care.
Yes, but even so im fairly sure a sticky rail will slow down the minecart if anything. Regardless it's not Mojang even looks at this forum so why do I care.
Actually, they do, and HAVE posted on ideas, if you are going to be rude, please do not continue to post on my thread. Thank you
I agree, that you have a point, but there is one major flaw with it: It is wrong.
You do argue that the acceleration of a booster rail is not enogh to counteract the acceleration of the gravity of a minecart. It is obvious that this only applies to vertical climbs, since minecarts are already able to move up slopes and move horizontally.
You furthermore argue that the decceleration of a minecart would happen so quickly, that mincart would not be able to transition from a normal slope to an upside down one, as the minecart would not be able to surpass the one vertical rail in the middle.
This is where it becomes interresting. The acceleration of a minecart by gravity is 16 meters per second². (Source: minecraftwiki). Now we have to compare this with the acceleration of a booster rail. Sadly, there are no literature values on this one. (At least I could not find any), so I had to test it by myself. According to my tests, accelerating minecarts are able to travel 10 Blocks in 1.4 seconds. This leads to an accelaration on the rail of: 10/1.4²= ca. 5.1 m/s². This value is not good by any means, and I would appreciate if someone could come up with a better testing method or result. (Just reply, I will not hesitate to change this post).
Seeing ths values, it becomes obvious that a vertical climb is not sustainable, so the minecart cannot go straight up indefinantly.
However, the real question is: Can a minecart transition to a upside down slope?
To answer this question: We have to calculate when the velocity of a minecart is fully deccelerated by the gravity minus the booster accelaration. The decelaration of the minecart, therefor is 10.9 m/s². The maximum velocity of a minecart going up a slope is the root of 2 times 8m/s= ca. 11.31m/s. This leads to the conclusion, that the longest time a vertical climb can be sustained is: (11.31m/s)/(10.9m/s²)= 1.04 seconds.(=t_1)
How many blocks can a minecart travel vertically given the time of 1.04 seconds and the decreasing velocity. If the number of blocks is greater than one,this post does make sence and cannot be critizised in this aspect. The number of blocks is equal to the integral from 0 to 1.04 over the function v(t) dt., with v(t) being 11.31-10.9t. This equals ca. 5.87.
As you can see, your point can be disproved using basic mathematics and about 15 minutes of research and calculating.
As I am not a motherspeaker, I would appreciate any effort to help me making this point more understandable.
I agree, that you have a point, but there is one major flaw with it: It is wrong.
Bold claim right off the bat
You do argue that the acceleration of a booster rail is not enogh to counteract the acceleration of the gravity of a minecart. It is obvious that this only applies to vertical climbs, since minecarts are already able to move up slopes and move horizontally.
Let's break the motion of any cart into forces. There is the force applied to the cart from the powered rails, lets called it applied force (Fa), next there is the force of friction, which opposes motion of an object, lets call this force of friction (Ff). Next there is the force of gravity, (Fg). Now lets make an equation. We want Fa to be greater than Fg (it's component along the axis of the rail, which is Fgsin(theta) where theta is the angle of slope, in minecraft this will be 45 or 90. There is also the frictional force, which is the coefficient of friction (μ) multiplied by the normal force, which is Fgcos(theta). Thus we get the equation Fa >= Fgsin(theta) + μFgcos(theta). Essentially if the left is greater than the right, the cart will accelerate, forwards, if right is greater it will accelerate backwards, and if it is balanced it will keep a constant velocity. Now lets imagine the slope is 90 degrees (vertical), which means we plug 90 into theta. sin(90) = 1 and cos(90) = 0 therefore the equation simplifies to Fa >= Fg , which becomes m*ap >= m*ag , which is mass independent, so ap >= ag where ap is the acceleration from the powered rail, and ag is the acceleration due to gravity. So, lets find out what each acceleration is. Since I couldn't find any information online about how a powered rail accelerates a minecart I did my own testing using redstone timers and detector rails. What I found is that a minecarts have top speeds of 8m/s, and they only need two powered rails to achieve that speed. With one powered rail it would take the cart 1.75 seconds to travel 8 meters, this gives a velocity of 4.57143, keep in mind that this number is the average velocity over the course of 8 meters. Using kinematics equations we can find the acceleration of the cart while it is on the powered rail. I will use the equation Vf2 = Vi2 + 2ad, where d is 1m (length of powered rail), a is what we are solving for, Vf is the final velocity (4.57143m/s), and Vi is the initial velocity (0m/s) plug those numbers in and you get an acceleration of 10.449m/s2 Great, now we have the acceleration a minecart will experience when on a powered rail. Now lets compare that to the gravitational acceleration. According to this http://minecraft.gamepedia.com/Entity#Motion_of_entities The acceleration of minecarts and boats is 16m/s2 which is greater than than the acceleration due to a powered rail. the net force on an object is the sum of all the forces on an object, so in out case Fnet = Fa + (-Fg) so, the net acceleration on this cart is going to be -5.55m/s2. So, even with power rails going all along the vertical you will a max height, I will use Vf2 = Vi2 + 2ad since it does not involve time, from this we get 5.76577m, or just under 6 blocks before you begin to reverse
Edit: Tried to explain it so anyone reading this could understand, and I I could have done this other ways, but whatever, it worked.
You furthermore argue that the decceleration of a minecart would happen so quickly, that mincart would not be able to transition from a normal slope to an upside down one, as the minecart would not be able to surpass the one vertical rail in the middle. If the vertical rail was less than 6 blocks than yes, it could get to an upside down rail.[quote]This is where it becomes interresting. The acceleration of a minecart by gravity is 16 meters per second². (Source: minecraftwiki). Now we have to compare this with the acceleration of a booster rail. Sadly, there are no literature values on this one. (At least I could not find any), so I had to test it by myself. According to my tests, accelerating minecarts are able to travel 10 Blocks in 1.4 seconds. This leads to an accelaration on the rail of: 10/1.4²= ca. 5.1 m/s². This value is not good by any means, and I would appreciate if someone could come up with a better testing method or result. (Just reply, I will not hesitate to change this post).Seeing ths values, it becomes obvious that a vertical climb is not sustainable, so the minecart cannot go straight up indefinantly.However, the real question is: Can a minecart transition to a upside down slope?To answer this question: We have to calculate when the velocity of a minecart is fully deccelerated by the gravity minus the booster accelaration. The decelaration of the minecart, therefor is 10.9 m/s². The maximum velocity of a minecart going up a slope is the root of 2 times 8m/s= ca. 11.31m/s. This leads to the conclusion, that the longest time a vertical climb can be sustained is: (11.31m/s)/(10.9m/s²)= 1.04 seconds.(=t_1)How many blocks can a minecart travel vertically given the time of 1.04 seconds and the decreasing velocity. If the number of blocks is greater than one,this post does make sence and cannot be critizised in this aspect. The number of blocks is equal to the integral from 0 to 1.04 over the function v(t) dt., with v(t) being 11.31-10.9t. This equals ca. 5.87. As you can see, your point can be disproved using basic mathematics and about 15 minutes of research and calculating.As I am not a motherspeaker, I would appreciate any effort to help me making this point more understandable.
Your initial condition "According to my tests, accelerating minecarts are able to travel 10 Blocks in 1.4 seconds. This leads to an accelaration on the rail of: 10/1.4²= ca. 5.1 m/s²." is wrong. the number you got from that is velocity, not acceleration. Regardless vertical rails are not sustainable, especially if it is going to be "sticky".
As you can see, your point can be disproved using basic mathematics and about 15 minutes of research and calculating.
I fail to see that, in-fact the math proves the opposite.
I think it would be better for something like a "chain rail" which would pull the minecart up the incline similar to a real roller coaster. As for upside down rails they could have additional bits which would "hold" the cart, similar to a roller coaster.
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Curse Premiumthat would be hilarious XD upside down 2x
Over 90% of all the things in Minecraft ignore gravity. Also, THIS IS A VIDEO GAME! Stop trying to apply real world logic to it. Gravity exists, but only to CERTAIN THINGS! And there are PLENTY of ways around gravity. In Minecraft, gravity isn't universal.
Oh, and if your rule is implemented, then i guess you won't be able to post any suggestions.
I see failures under a tree aka the Online dater owners who have the marry plugin because they're loners and cant get a real girlfriend or boyfriend because they apparently are inmature 16 year olds to under stand what a real girlfriend in because they sit in their room online dating on roblox or minecraft with some 8 year old girl and the boy being 18. online daters are excuses.
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Curse PremiumGlad you like the idea guys
Yes, but even so im fairly sure a sticky rail will slow down the minecart if anything. Regardless it's not Mojang even looks at this forum so why do I care.
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But, you shouldn't use slime blocks, just slimeballs. Slime blocks would take too many resources.
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Curse PremiumActually, they do, and HAVE posted on ideas, if you are going to be rude, please do not continue to post on my thread. Thank you
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Curse PremiumGlad you like it
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Curse PremiumThanks, happy you love it XD
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Curse Premiumsounds like your hype is real XD
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Curse PremiumThank you for further explaining.
I like CyanogenMod 13 and coding for my phone.. Yep. That's all.
Bold claim right off the bat
Let's break the motion of any cart into forces. There is the force applied to the cart from the powered rails, lets called it applied force (Fa), next there is the force of friction, which opposes motion of an object, lets call this force of friction (Ff). Next there is the force of gravity, (Fg). Now lets make an equation. We want Fa to be greater than Fg (it's component along the axis of the rail, which is Fgsin(theta) where theta is the angle of slope, in minecraft this will be 45 or 90. There is also the frictional force, which is the coefficient of friction (μ) multiplied by the normal force, which is Fgcos(theta). Thus we get the equation Fa >= Fgsin(theta) + μFgcos(theta). Essentially if the left is greater than the right, the cart will accelerate, forwards, if right is greater it will accelerate backwards, and if it is balanced it will keep a constant velocity. Now lets imagine the slope is 90 degrees (vertical), which means we plug 90 into theta. sin(90) = 1 and cos(90) = 0 therefore the equation simplifies to Fa >= Fg , which becomes m*ap >= m*ag , which is mass independent, so ap >= ag where ap is the acceleration from the powered rail, and ag is the acceleration due to gravity. So, lets find out what each acceleration is. Since I couldn't find any information online about how a powered rail accelerates a minecart I did my own testing using redstone timers and detector rails. What I found is that a minecarts have top speeds of 8m/s, and they only need two powered rails to achieve that speed. With one powered rail it would take the cart 1.75 seconds to travel 8 meters, this gives a velocity of 4.57143, keep in mind that this number is the average velocity over the course of 8 meters. Using kinematics equations we can find the acceleration of the cart while it is on the powered rail. I will use the equation Vf2 = Vi2 + 2ad, where d is 1m (length of powered rail), a is what we are solving for, Vf is the final velocity (4.57143m/s), and Vi is the initial velocity (0m/s) plug those numbers in and you get an acceleration of 10.449m/s2 Great, now we have the acceleration a minecart will experience when on a powered rail. Now lets compare that to the gravitational acceleration. According to this http://minecraft.gamepedia.com/Entity#Motion_of_entities The acceleration of minecarts and boats is 16m/s2 which is greater than than the acceleration due to a powered rail. the net force on an object is the sum of all the forces on an object, so in out case Fnet = Fa + (-Fg) so, the net acceleration on this cart is going to be -5.55m/s2. So, even with power rails going all along the vertical you will a max height, I will use Vf2 = Vi2 + 2ad since it does not involve time, from this we get 5.76577m, or just under 6 blocks before you begin to reverse
Edit: Tried to explain it so anyone reading this could understand, and I I could have done this other ways, but whatever, it worked.
Your initial condition "According to my tests, accelerating minecarts are able to travel 10 Blocks in 1.4 seconds. This leads to an accelaration on the rail of: 10/1.4²= ca. 5.1 m/s²." is wrong. the number you got from that is velocity, not acceleration. Regardless vertical rails are not sustainable, especially if it is going to be "sticky".
I fail to see that, in-fact the math proves the opposite.
I think it would be better for something like a "chain rail" which would pull the minecart up the incline similar to a real roller coaster. As for upside down rails they could have additional bits which would "hold" the cart, similar to a roller coaster.