I'm not the best with Redstone, and I've been tinkering with this idea for a little while with little success. I'm trying to make a sort of OR Gate using four inputs, but here's the catch: I want it to activate when any three of the inputs are active. Is there a way to do this with redstone, or might my time be better spent just using scoreboards and such? If so, how might I do that?
Yeah, you're over complicating it. You don't need a 4 input Or gate (which doesn't exist). However, I'm not sure if the above solution is the best. I assume you want ANY 3 to activate it. I'll be back in a bit with a design
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This is definitely very much possible. Unfortunately I'm unable to make a model as I'm going to be fairly busy for the foreseeable future. You'd have to use something with cutting of power sources and stuff, but it's pretty doable. And it doesn't have a ton going on, just a lot of basis for a layout. Trust me, it's perfectly possible
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Even though my Join date is in 2014, I tried the demo on 8/30/2012, and bought the game two days later on 9/1/2012. So hipster
I'm confused. I understand the concept and that mine is restricted to certain inputs though to one with any three inputs acting as an AND gate before OR that would not be complicated. Are you guys having trouble with it? I just posted a fast solution to what could be a simple problem where there may not need be variable inputs in play.
Hehe, right when I finally get to work other people already have it solved If you still need help with it, I devised a way (just have a bunch of OR gates for each pair of lines, and one big line activated by any 1, inverted)
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Even though my Join date is in 2014, I tried the demo on 8/30/2012, and bought the game two days later on 9/1/2012. So hipster
None of those are OR gates. An OR Gate only depends on 1 Input. If all are off, Output will be off (false). If 1 or more are on, Output will be on (true).
Yeah, I know, but I didn't know any better way to say it.
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I'm still kinda new at this, but for simplicity's sake, wouldn't it make more sense to make 2 OR gates, then have the output from those two feed into a 3rd OR gate?
I'm still kinda new at this, but for simplicity's sake, wouldn't it make more sense to make 2 OR gates, then have the output from those two feed into a 3rd OR gate?
Holy crap he's right.
Wait no because that would work if any number was on, not just 3
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I took discrete mathematics in college 2-3 years ago, and logic gates gave me huge headaches. When I typed that this morning, it was PC (pre-coffee) so the gears in my head were still the wooden ones, not the diamond ones (haha!). After reading both of your replies and working this out in my head, I can see why I'm totally wrong on it.
I still think there's a simpler way to do it that what's been posted. I'm going to work on it a little and see if I can come up with something. There'll be pix if I can, or a great big frowny face if I can't.
Edit: Ok scratch that. I just suck at logic gates. It sounds so simple, but I can't work out a simpler way than what was posted. Sorry guys.
It's cool. I myself have thought of a way that's decidedly more simple. However it's less compact. So that's why I haven't posted it I think the way shown pretty much sums it up, don't you guys? nice job on it btw, MajorMCDoom
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Even though my Join date is in 2014, I tried the demo on 8/30/2012, and bought the game two days later on 9/1/2012. So hipster
Heh, can't wait until I figure out logic notation as for now, I only know what logic gates I've taught myself (and they're actually much simpler than expected). But still, they were enough to build what is technically a Turing complete computer even though it's really just a programmable combo lock :3
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Even though my Join date is in 2014, I tried the demo on 8/30/2012, and bought the game two days later on 9/1/2012. So hipster
I'm not the best with Redstone, and I've been tinkering with this idea for a little while with little success. I'm trying to make a sort of OR Gate using four inputs, but here's the catch: I want it to activate when any three of the inputs are active. Is there a way to do this with redstone, or might my time be better spent just using scoreboards and such? If so, how might I do that?
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Do you mean something like this?
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Yeah, you're over complicating it. You don't need a 4 input Or gate (which doesn't exist). However, I'm not sure if the above solution is the best. I assume you want ANY 3 to activate it. I'll be back in a bit with a design
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This is definitely very much possible. Unfortunately I'm unable to make a model as I'm going to be fairly busy for the foreseeable future. You'd have to use something with cutting of power sources and stuff, but it's pretty doable. And it doesn't have a ton going on, just a lot of basis for a layout. Trust me, it's perfectly possible
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I'm confused. I understand the concept and that mine is restricted to certain inputs though to one with any three inputs acting as an AND gate before OR that would not be complicated. Are you guys having trouble with it? I just posted a fast solution to what could be a simple problem where there may not need be variable inputs in play.
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If you want something which will activate if ANY 3 of the inputs are on, but NOT if all 4 are on, then this will do the trick.
Basically it's a 3x3x7 tower which is completely radially symmetrical.
You can extract the output from any side of this tower by adding a little extraction module.
Let me know if you want the tutorial and I can make one for you. =)
Hehe, right when I finally get to work other people already have it solved If you still need help with it, I devised a way (just have a bunch of OR gates for each pair of lines, and one big line activated by any 1, inverted)
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Sorry about that, I lost track of this topic for a few days...
Yeah, I know, but I didn't know any better way to say it.
Thanks guys! Seems these should work perfectly.
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Here's my tutorial. Please note that steps 8 and 9 can be put on ANY side of the tower.
I'm still kinda new at this, but for simplicity's sake, wouldn't it make more sense to make 2 OR gates, then have the output from those two feed into a 3rd OR gate?
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Okay, so you have inputs A B C D.
First OR gate is on if either A or B are on.
Second OR gate is on if either C or D are on.
Third OR gate is on if either of the first two are on.
You end up with something that's on if any input is on.
Holy crap he's right.
Wait no because that would work if any number was on, not just 3
Even though my Join date is in 2014, I tried the demo on 8/30/2012, and bought the game two days later on 9/1/2012. So hipster
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I took discrete mathematics in college 2-3 years ago, and logic gates gave me huge headaches. When I typed that this morning, it was PC (pre-coffee) so the gears in my head were still the wooden ones, not the diamond ones (haha!). After reading both of your replies and working this out in my head, I can see why I'm totally wrong on it.
I still think there's a simpler way to do it that what's been posted. I'm going to work on it a little and see if I can come up with something. There'll be pix if I can, or a great big frowny face if I can't.
Edit: Ok scratch that. I just suck at logic gates. It sounds so simple, but I can't work out a simpler way than what was posted. Sorry guys.
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It's cool. I myself have thought of a way that's decidedly more simple. However it's less compact. So that's why I haven't posted it I think the way shown pretty much sums it up, don't you guys? nice job on it btw, MajorMCDoom
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Thanks, Xystem4.
JaRyCu, if you write out the system in propositional logic, it's very simply:
(¬A∧B∧C∧D)∨(A∧¬B∧C∧D)∨(A∧B∧¬C∧D)∨(A∧B∧C∧¬D)
You can write it in other ways, but you'd be hard pressed to make it any shorter than that.
MazeCraft's solution was very cool, since it was actually using arithmetic, not just logic:
2 > (4-A-B-C-D) > 0
The beautiful thing about notation is, you don't have to guess if there's a simpler way.
As Xystem4 said, there is the goal here of making it compact in redstone as well.
So if you want to pursue making a more elegant redstone contraption, go for it.
If you want to find a way to simplify the propositional logic, don't waste your time.
Edit: Woops, sorry, just saw your edit.
Heh, can't wait until I figure out logic notation as for now, I only know what logic gates I've taught myself (and they're actually much simpler than expected). But still, they were enough to build what is technically a Turing complete computer even though it's really just a programmable combo lock :3
Even though my Join date is in 2014, I tried the demo on 8/30/2012, and bought the game two days later on 9/1/2012. So hipster
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