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Hi, i am in the middle of desighning my player dungeon, however i have come across a problem.
before you enter the dungeon i have a room with 6 chests hidden in the walls with pistons and a lever to open each one of them. the idea is that you enter this room and are told to pick one of the 6 chests, in each chest are items that will aid you in the dungeon ahead, however i only want the players to be able to open 1 chest only per run of the dungeon. So i am trying to desighn a deadlock, meaning that when you pull the lever to open your chosen chest it allso sets off a chain reaction that pushes piston blocks over all the levers that open the chests, making it impossable to open any of the 5 remaining chests, making sure you are stuck with what you chose.

I have been trying to complete this desighn but am struggling with the finishing touches, when the power is turned off on one lever to open up the chest i need power to be turned on to the redstone circuits connecting to the deadlock pistons. Any help on this matter would be apreciated.

Thanks.

or you can just make each and every one of the levers have a piston coming down on the redstone thus "killing" the power but this mean you will have to rewire those sections after each use

EDIT or if they all come to a single pint just use the non sticky piston to push said block away from the rest

Thanks for the info, may be worth while reducing the number of chests to simplify the matter.
Ive only been playing this game for 1 1/2 months now but im getting into very complicated redstone circuits.
most of what u said makes sense, thought what does OR mean?

i am allso looking for other likeminded minecraft players to join with me and start creation of a very large city, or just to have some minecraft fun on xbox.

Thanks alot, ive printed off all that info you linked me and will spend the next few days studying it all in detail.
Thanks for the help

Quote from Crackshotify

or you can just make each and every one of the levers have a piston coming down on the redstone thus "killing" the power but this mean you will have to rewire those sections after each use

EDIT or if they all come to a single pint just use the non sticky piston to push said block away from the rest

If you have the 'cutter' piston come down over a drop in level of the redstone line, it cuts the circuit without disturbing the redstone itself. When the piston withdraws, the circuit can go live again.

In other words, a redstone line drops one level and continues. The piston head comes down over the first lower-level redstone, so that it meets the edge of the higher-level redstone line, and cuts the circuit at the point where the redstone goes over the edge and down the block to the lower level. The actual, placed redstone is never touched or disturbed, but current can no longer pass over the edge and down to the lower level. (or up, I guess, depending on which way it's flowing).



So... in the OP's setup..

I'd do it like this: All chests have a piston-block cover that's attached to an inverter, and all are connected to one live line. Cut the live line, and they all close. Each chest has a lever that is wired to it's chests' inverter, and also to the cutter piston for the main line.

Throw one lever, and it sends a signal to two places: it's local inverter (to maintain power to the one chest the player chose, keeping the cover to that one open when the main line is cut), and to the cutter piston (which drops on an edge at the power source for the main line, and thus activates the covers for all the other chests).

Unfortunately, this would mean that if you turned the first switch off, they'd all open up again. The cutter piston would actually have to come down on the line & permanently break it if you wanted a one-shot deal, which would require resetting that one piece of redstone each time.

I suppose if, in between the incoming line to the cutter and the cutter itself, you set up a simple memory circuit with a reset switch, you could avoid that. Of course, how much room do you want this whole mechanism to occupy? lol

Quote from hiram13pm

Unfortunately, this would mean that if you turned the first switch off, they'd all open up again. The cutter piston would actually have to come down on the line & permanently break it if you wanted a one-shot deal, which would require resetting that one piece of redstone each time.

Or have the cutter piston actually push a block of glass into place, so that when the piston retracts the doors are actually deadlocked.

Quote from Mike_R_Hammer

Or have the cutter piston actually push a block of glass into place, so that when the piston retracts the doors are actually deadlocked.

That would still mean having to go in and reset the mechanism for the next run. Check my edit to that post; a memory cell with a reset would avoid having to go all the way into the guts of the system to reset it. Just flip the original lever back into place & then hit a button in the "control room"

It should be pretty easy with inverters. I assume you're using two different doors/closing mechanisms for each chest?

Quote from hiram13pm

That would still mean having to go in and reset the mechanism for the next run. Check my edit to that post; a memory cell with a reset would avoid having to go all the way into the guts of the system to reset it. Just flip the original lever back into place & then hit a button in the "control room"

You're right. +1